Tuesday, December 15, 2015

NCDF(S, 2, 2, L, 3): Example 1: S = [1, 2, 3, 4, 5, 6, 7, 8]




Problem
  
This post is a detailed example of computing individual elements of NCDF(S, 2, 2, L, 3) at each of the three scales on S = [1, 2, 3, 4, 5, 6, 7, 8]. NCDF(S, 2, 2, L, J) notation is defined here. This notation is based on the notation introduced in Chapters 3 and 4 in "Ripples in Mathematics" by A. Jensen & A. la Cour-Harbo.



NCDF(S, 2, 2, 1, 3): Scale L = 1
  
Figures 1 and 2 show the formulas for the elements of S and D at scale L = 1. Figure 3 shows an example of computing the first scale of the signal S = [1, 2, 3, 4, 5, 6, 7, 8]. 
Figure 1. Formulas for individual elements of S at scale L = 1
Figure 2. Formulas for individual elements of D at scale L = 1
Figure 3. Computing elements of S and D at scale L = 1



NCDF(S, 2, 2, 2, 3): Scale L = 2
  
Figure 4 shows the individual formulas for S and D at scale L = 2. Figure 5 shows the computation of individual elements of S and D of the sample [1, 2, 3, 4, 5, 6, 7, 8] at scale L = 2.
Figure 4. Formulas for individual elements of S and D at scale L = 2
Figure 5. Computing elements of S and D at scale L = 2



NCDF(S, 2, 2, 3, 3): Scale L = 3
  
Figure 6 shows the individual formulas for S and D at scale L = 3. Figure 7 shows the computation of individual elements of S and D of the sample [1, 2, 3, 4, 5, 6, 7, 8] at scale L = 3.
Figure 6. Formulas for individual elements of S and D at scale L = 3
Figure 7. Computing elements of S and D at scale L = 3



Summary of NCDF(S, 2, 2, 3, 3) at All Three Scales
  
Figure 8 summarizes the three scales of NCDF(S, 2, 2, 3, 3), where S = [1, 2, 3, 4, 5, 6, 7, 8].

Figure 8. Summary of NCDF(S, 2, 2, 3, 3) at all three scales